pibbuR
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Return to Monkey Island (return of Return of Monkey Island?) will be released in about 4 hours. Still time to prepurchase, which comes with a gift: "a highly exclusive and entirely useless Horse Armor in their inventory". At least this time said armoUr is free.
pibbuR who still has 4 hourse to decide to, then decide not to, then decide to, then ... prepurchase.
pibbuR who still has 4 hourse to decide to, then decide not to, then decide to, then ... prepurchase.
That's a nice one, logical operators at their best. 
The Ig Nobelprices for 2022 is official: https://gizmodo.com/here-are-the-winners-of-the-2022-ig-nobel-prize-1849545482
One quote:
"For literature, the Ig Nobel was given to Eric Martínez, Francis Mollica, and Edward Gibson for showing that legal jargon may not be the main reason why lawyers are so hard to understand. Instead, as their paper’s title aptly describes: “Poor Writing, Not Specialized Concepts, Drives Processing Difficulty in Legal Language.”
pibbuR
One quote:
"For literature, the Ig Nobel was given to Eric Martínez, Francis Mollica, and Edward Gibson for showing that legal jargon may not be the main reason why lawyers are so hard to understand. Instead, as their paper’s title aptly describes: “Poor Writing, Not Specialized Concepts, Drives Processing Difficulty in Legal Language.”
pibbuR
Interesting, the Ig Nobels, first time I hear about that.
That's depressing...
Then you've really missed something. You'll find all about it here: https://improbable.com/ (maybe you've already found the site).
And while we're at it, in case you also missed this one, the Darwing Awards (https://darwinawards.com/) "which honor those who tip chlorine into our gene pool, by accidentally removing their own DNA from it during the spectacular climax of a 'great idea' gone veddy, veddy wrong."
pibbuR who admits the latter may be too macabre for some.
1^x = 1 for all x
so you first just have to solve
(x*x-5x+5) = 1 ; this gives you x=1 or x=4
x^0 = 1 for all x <> 0
so you then have to solve
(x*x-11x+30)=0 ; this gives you x=5 or x=6
so x is element from {1;4;5;6}
There are actually 2 more solutions (both real).
pibbuR who got the first 4, but not the last two.
pibbuR who got the first 4, but not the last two.
{1;4;5;6} should be all real solutions - maybe with some imagination some imaginary numbers are flying in?
Consider (x*x-5x+5) = -1. If either of the solutions to that one (2 and 3) makes (x*x-11x+30) even, those are also solutions. 2 and 3 do that. So {1;2,3,4;5;6} is the complete set of solutions. Clever and funny methinks.
pibbuR who as said, did not find those 2 without an explictit hint.
PS: For fun I tried the equation in my math packages.
- Matlab, using the symbolic math package, could solve the individual polynoms, but not the complete equation. No surpise, really, Matlab focuses on numerical computing.
- Mathematica found {1;4;5;6}
- Maple found all of them, which surprised me, since I've always thought Mathematica was the strongest of the two.
DS.
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The problem: the function (x*x-5*x+5)^(x*x-11*x+30) is not continous over the real number line:
Attachments
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I should be/am embarassed. But what does steady mean here? Continuous?
pibbuR
pibbuR
I was about to say, luckily the negative segment of x²-5x+5 doesn't include any root or we may have been in trouble Yes, x is complex for several sub-ranges, but the discrete values are fine.
I knew about the Darwin Awards, there are some very good ones even if the humour is not for everyone.
Yes, x is complex for several sub-ranges, but the discrete values are fine.I knew about the Darwin Awards, there are some very good ones even if the humour is not for everyone.
I'm not sure if that's a continuity problem, or just a graphic representation problem.
If I'm not too confused by this obscure part of calculus, x^y is real except for negative values of x, where it is only real forrational integer values of y (and there is a condition for the result to be either negative or positive).
But I don't know if such a function is continuous on the negative part of x²-5x+5 (just complex) or if it is discrete. Plotting it as a complex function might give an idea but I don't have a fancy program to do that.
If I'm not too confused by this obscure part of calculus, x^y is real except for negative values of x, where it is only real for
But I don't know if such a function is continuous on the negative part of x²-5x+5 (just complex) or if it is discrete. Plotting it as a complex function might give an idea but I don't have a fancy program to do that.
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Here's a real and imaginary (stipled) plot of the function using Mathematica. The imaginary part passes 0 for x=2 and 3, where the real part is 1.
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Now for the commercials: Mathematica, Maple and Matlab all have comparably low prices (around 200-300USD) for individual home/hobby users. Well worth it IMO. For less than the cost of a 3080Ti you can buy all of them.
pibbuR who sadly received no money for posting this.
PS. There are also freee math software. One is Octave which as said is a Matlab clone. There are also others. And of course Python libraries. DS.
pibbuR who sadly received no money for posting this.
PS. There are also freee math software. One is Octave which as said is a Matlab clone. There are also others. And of course Python libraries. DS.
Impressing.